A Shunt generator running at 1000 rpm has generated emf of 100 V.
If the speed increases to 1200 rpm, the generated emf will be nearly
A. 120 V
B. 140 V
C. 175 V
D. 240 V
Show Answer
Answer: A
Share your understanding of this question with the correct explanation.
Mike
2
Explanation
To determine the approximate generated emf when the speed of a shunt generator increases from 1000 rpm to 1200 rpm, we can use the formula:
Emf2 / Emf1 = (N2 / N1) * (Φ2 / Φ1)
Where:
- Emf1 is the initial generated emf (100 V)
- Emf2 is the final generated emf (unknown)
- N1 is the initial speed (1000 rpm)
- N2 is the final speed (1200 rpm)
- Φ1 is the initial magnetic flux
- Φ2 is the final magnetic flux
Assuming the magnetic flux remains constant, we can simplify the equation to:
Emf2 / Emf1 = N2 / N1
Plugging in the values: Emf2 / 100 = 1200 / 1000
Cross-multiplying and solving for Emf2: Emf2 = (1200 / 1000) * 100 Emf2 = 12 * 100 Emf2 = 120 V
Therefore, the generated emf will be approximately 120 V when the speed increases to 1200 rpm. Thus, the correct answer is A.