Two parallel plates are separated by a distance D charged by V volt.
The field intensity E is given by,
A. V × D
B. V / D
C. V × D²
D. V² / D
Show Answer
Answer: B
Share your understanding of this question with the correct explanation.
The field intensity E between two parallel plates separated by a distance D and charged by V volts is given by V / D. Therefore, the correct answer is B: “V / D.”
Here’s a further explanation:
When two parallel plates are charged with a potential difference V volts and separated by a distance D, an electric field is established between the plates. The field intensity E represents the strength of the electric field and is defined as the electric field per unit distance.
In this case, the field intensity E is given by the ratio of the potential difference V to the separation distance D. Mathematically, it can be expressed as:
E = V / D
The electric field intensity is directly proportional to the potential difference and inversely proportional to the separation distance between the plates.
Option A, V × D, represents the product of the potential difference V and the separation distance D, but this does not correctly represent the field intensity E.
Option C, V × D², represents the product of the potential difference V and the square of the separation distance D, but this also does not correctly represent the field intensity E.
Option D, V² / D, represents the square of the potential difference V divided by the separation distance D, but this is not the correct expression for the field intensity E.
Therefore, the correct answer is B: “V / D,” which correctly represents the relationship between the potential difference and the separation distance in determining the field intensity between two parallel plates