A 4 pole dc motor with armature winding resistance of 0.6 ohm receives a supply of 230 Volt.

If the back emf produced during running condition is equal to 210 volt.

Calculate the current flowing through the armature at this point.

A. 43 Amp.

B. 44.47 Amp.

C. 33.33 Amp.

D. 29 Amp.

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Answer: C

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Mike
2
**explantion**

To calculate the current flowing through the armature of the DC motor, we can use Ohm’s law.

The armature current (Ia) can be calculated using the formula:

Ia = (V - Eb) / Ra

Where:

V is the supply voltage (230 V)

Eb is the back electromotive force (210 V)

Ra is the armature winding resistance (0.6 ohm)

Substituting the given values into the formula:

Ia = (230 V - 210 V) / 0.6 ohm

Ia = 20 V / 0.6 ohm

Ia ≈ 33.33 A

Therefore, the current flowing through the armature at this point is approximately 33.33 Amp (Option C).