A 4 pole DC shunt generator having a wave winding supplies 50 lamps, each of 60 W at 120 V.
The armature and field resistance are 0.2 Ω and 60 Ω respectively.
The current in each armature conductor is
A. 11.5 A.
B. 13.5 A.
C. 23 A.
D. 27 A.
Answer: B
Share your understanding of this question with the correct explanation.
To determine the current in each armature conductor, we need to calculate the total load current and divide it by the total number of armature conductors.
Given:
Number of lamps = 50
Power of each lamp = 60 W
Voltage of each lamp = 120 V
Armature resistance = 0.2 Ω
Total load power = Number of lamps × Power of each lamp = 50 × 60 W = 3000 W
Total load current = Total load power / Voltage = 3000 W / 120 V = 25 A
Since it is a 4-pole generator, there are 4 sets of armature conductors.
Number of armature conductors per set = Total number of armature conductors / Number of poles = (4 × Number of conductors per pole) / Number of poles
Since it is a wave winding, the number of conductors per pole is equal to the total number of conductors divided by the number of poles:
Number of conductors per pole = Total number of conductors / Number of poles = 50 / 4 = 12.5
Since the number of conductors must be a whole number, we can consider 12 conductors per pole.
Number of armature conductors per set = (4 × 12) / 4 = 12
Now we can calculate the current in each armature conductor:
Current in each armature conductor = Total load current / Number of armature conductors per set = 25 A / 12 = 2.083 A
Therefore, the current in each armature conductor is approximately 2.083 A.
So, the closest answer is A. 2.083 A.