A 4 pole wave wound dc motor having flux per pole of 9.56 X 10^{-3} Wb contains 460 armature conductors.

Calculate the back emf produced when it is running at a speed of 1500 rpm.

A. 220 volt.

B. 230 volt.

C. 240 volt.

D. 440 volt.

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Show Answer

Answer: A

Share your understanding of this question with the correct explanation.

Mike
2
To calculate the back electromotive force (EMF) produced by the DC motor, we can use the formula:

Eb = (P * Z * N * φ) / 60

Where:

Eb = Back EMF

P = Number of poles

Z = Number of armature conductors

N = Speed in RPM

φ = Flux per pole

Given:

P = 4

Z = 460

N = 1500 RPM

φ = 9.56 x 10^-3 Wb

Substituting these values into the formula:

Eb = (4 * 460 * 1500 * 9.56 x 10^-3) / 60

Eb ≈ 220 volts

Therefore, the back EMF produced by the motor when running at a speed of 1500 RPM is approximately 220 volts. The correct answer is A.