A 4 pole wave wound dc motor having flux per pole of 9.56 X 10-3 Wb contains 460 armature conductors.
Calculate the back emf produced when it is running at a speed of 1500 rpm.
A. 220 volt.
B. 230 volt.
C. 240 volt.
D. 440 volt.
Answer: A
Share your understanding of this question with the correct explanation.
To calculate the back electromotive force (EMF) produced by the DC motor, we can use the formula:
Eb = (P * Z * N * φ) / 60
Where:
Eb = Back EMF
P = Number of poles
Z = Number of armature conductors
N = Speed in RPM
φ = Flux per pole
Given:
P = 4
Z = 460
N = 1500 RPM
φ = 9.56 x 10^-3 Wb
Substituting these values into the formula:
Eb = (4 * 460 * 1500 * 9.56 x 10^-3) / 60
Eb ≈ 220 volts
Therefore, the back EMF produced by the motor when running at a speed of 1500 RPM is approximately 220 volts. The correct answer is A.