For there to be is a continuous logic path from left to right across the rung:
A. I/1, 1/2, and 1/3 must all be at logic 1.
B. I/1, 1/2, and 1/3 must all be at logic 0.
C. I/1 and 1/2 or 1/3 must be at logic 1.
D. I/1 and 1/2 or 1/3 will be at logic 0.
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