# When a PB-switch-logic Wired-Exclusive-OR gate is employed in a motor control circuit, When both switches are activated, the PB-switch-logic output, taken at the common node forming the OR gate of the two series-connected switch inputs, is ___ volts

When a PB-switch-logic Wired-Exclusive-OR gate is employed in a motor control circuit,

When both switches are activated, the PB-switch-logic output, taken at the common node forming the OR gate of the two series-connected switch inputs, is __________ volts.

B) 120
C) either 120 or zero
D) zero

Share your understanding of this question with the correct explanation.

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Explanation:

When a PB-switch-logic Wired-Exclusive-OR gate is employed in a motor control circuit, when both switches are activated, the PB-switch-logic output, taken at the common node forming the OR gate of the two series-connected switch inputs, is zero volts.

An Exclusive-OR gate (XOR gate) is a digital logic gate that outputs true (1) when the number of true inputs is odd. In the case of a PB-switch-logic, the XOR gate is used to control the motor circuit based on the states of two switches (Push Buttons, PB).

Here’s a breakdown of the options and why option D is the correct answer:

A) Any of the answers: This option is not correct because there is a specific voltage condition when both switches are activated, as explained below.

B) 120: This option is not correct because the output voltage of an XOR gate is not a fixed value like 120 volts. The output of an XOR gate will depend on the logic states of its input.

C) Either 120 or zero: This option is not correct. For two switches connected through an XOR gate, when both switches are activated (both are ON or closed), the XOR gate output will be zero volts, not 120 volts.

D) Zero: This is the correct answer. When both switches in the XOR gate are activated (both are ON or closed), the XOR gate’s output will be zero volts. This is because the XOR gate outputs a logical high (1) when the inputs are different, and a logical low (0) when the inputs are the same. In this case, since both inputs are the same (both switches are activated), the output is zero volts.